I’m sure this could be done better, so just wondering how you would compare all values in two lists, returning true if all values are the same. My current solution: secret = [3,4,5,1,3,6] challenge = [3,4,5,1,3,6] List.map2 (==) secret challenge |> List.all (\c -> c == True) --> True I’d like to…

Isn’t comparing the lists directly the same? In elm repl: > secret = [3,4,5,1,3,6] [3,4,5,1,3,6] : List number > challenge = [3,4,5,1,3,6] [3,4,5,1,3,6] : List number > (secret == challenge) True : Bool > challenge = [3,4,5,1,3,5] [3,4,5,1,3,5] : List number > (secret == challenge) Fa…

Simplify list compare logic

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Libbum February 18, 2019, 10:12am 3

Hah! Of course it is! Sorry, I was looking for complexity where there shouldn’t have been.

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Simplify list compare logic

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