I’m sure this could be done better, so just wondering how you would compare all values in two lists, returning true if all values are the same. My current solution: secret = [3,4,5,1,3,6] challenge = [3,4,5,1,3,6] List.map2 (==) secret challenge |> List.all (\c -> c == True) --> True I’d like to…

Isn’t comparing the lists directly the same? In elm repl: > secret = [3,4,5,1,3,6] [3,4,5,1,3,6] : List number > challenge = [3,4,5,1,3,6] [3,4,5,1,3,6] : List number > (secret == challenge) True : Bool > challenge = [3,4,5,1,3,5] [3,4,5,1,3,5] : List number > (secret == challenge) Fa…

Simplify list compare logic

Learn

Libbum February 18, 2019, 10:12am 3

Hah! Of course it is! Sorry, I was looking for complexity where there shouldn’t have been.

Topic		Replies	Views
Lazy evaluated map Learn	7	1477	December 11, 2021
Error msg does not make sense Learn	9	898	October 10, 2018
Proposal: pattern for dealing with empty lists Request Feedback	15	2897	June 30, 2019
New package: elm-list-cartesian Show and Tell	5	816	September 9, 2021
List.map optimization options Show and Tell	14	1888	June 20, 2021

Simplify list compare logic

Related topics