I’m sure this could be done better, so just wondering how you would compare all values in two lists, returning true if all values are the same. My current solution: secret = [3,4,5,1,3,6] challenge = [3,4,5,1,3,6] List.map2 (==) secret challenge |> List.all (\c -> c == True) --> True I’d like to just use the core, but examples using List.Extra or something else would be interesting for my education. Specifically, I think this may be a time I could use the >> operator, but I have trouble conceptualising its use.

Isn’t comparing the lists directly the same? In elm repl: > secret = [3,4,5,1,3,6] [3,4,5,1,3,6] : List number > challenge = [3,4,5,1,3,6] [3,4,5,1,3,6] : List number > (secret == challenge) True : Bool > challenge = [3,4,5,1,3,5] [3,4,5,1,3,5] : List number > (secret == challenge) False : Bool (Note that parentheses are needed because of a bug in elm repl if I remember correctly) Or did I miss something? Maybe you want another way as an exercise? Also your solution won’t work if lists have a different length as List.map2 ignores extra values: > challenge = [3,4,5,1,3,6,7] [3,4,5,1,3,6,7] : List number > List.map2 (==) secret challenge |> List.all (\c -> c == True) True : Bool

Simplify list compare logic

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Libbum February 18, 2019, 10:12am 3

Hah! Of course it is! Sorry, I was looking for complexity where there shouldn’t have been.

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Simplify list compare logic

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